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Commit 8e9b2689 authored by Martin Reinecke's avatar Martin Reinecke
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datatype patrol

parent 09ce0bd3
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Healpix_cxx/healpix_base.cc
View file @ 8e9b2689
......@@ -100,9 +100,9 @@ namespace {
2: pixel center is inside the shape, but maybe not the complete pixel
3: pixel lies completely inside the shape */
template<typename I, typename I2> inline void check_pixel (int o, int order_,
int omax, int zone, rangeset<I2> &pixset, I pix, vector<pair<I,int> > &stk,
bool inclusive, int &stacktop)
template<typename I, typename I2> inline void check_pixel (size_t o, size_t order_,
size_t omax, size_t zone, rangeset<I2> &pixset, I pix, vector<pair<I,size_t> > &stk,
bool inclusive, size_t &stacktop)
{
if (zone==0) return;
......@@ -114,7 +114,7 @@ template<typename I, typename I2> inline void check_pixel (int o, int order_,
pixset.append(pix<<sdist,(pix+1)<<sdist); // output all subpixels
}
else // (1<=zone<=2)
for (int i=0; i<4; ++i)
for (size_t i=0; i<4; ++i)
stk.push_back(make_pair(4*pix+3-i,o+1)); // add children
}
else if (o>order_) // this implies that inclusive==true
......@@ -145,7 +145,7 @@ template<typename I, typename I2> inline void check_pixel (int o, int order_,
if (order_<omax) // check sublevels
{
stacktop=stk.size(); // remember current stack position
for (int i=0; i<4; ++i) // add children in reverse order
for (size_t i=0; i<4; ++i) // add children in reverse order
stk.push_back(make_pair(4*pix+3-i,o+1));
}
else // at resolution limit
......@@ -326,12 +326,12 @@ template<typename I> template<typename I2>
crpdr[o] = (radius+dr>pi) ? -1. : cos(radius+dr);
crmdr[o] = (radius-dr<0.) ? 1. : cos(radius-dr);
}
vector<pair<I,int> > stk; // stack for pixel numbers and their orders
vector<pair<I,size_t> > stk; // stack for pixel numbers and their orders
stk.reserve(12+3*omax); // reserve maximum size to avoid reallocation
for (int i=0; i<12; ++i) // insert the 12 base pixels in reverse order
stk.push_back(make_pair(I(11-i),0));
int stacktop=0; // a place to save a stack position
size_t stacktop=0; // a place to save a stack position
while (!stk.empty()) // as long as there are pixels on the stack
{
......@@ -347,7 +347,7 @@ template<typename I> template<typename I2>
if (cangdist>crpdr[o])
{
int zone = (cangdist<cosrad) ? 1 : ((cangdist<=crmdr[o]) ? 2 : 3);
size_t zone = (cangdist<cosrad) ? 1 : ((cangdist<=crmdr[o]) ? 2 : 3);
check_pixel (o, order_, omax, zone, pixset, pix, stk, inclusive,
stacktop);
......@@ -477,7 +477,7 @@ template<typename I> template<typename I2>
}
else // scheme_ == NEST
{
int oplus = 0;
size_t oplus = 0;
if (inclusive)
{
MR_assert ((I(1)<<(order_max-order_))>=fact,
......@@ -486,13 +486,13 @@ template<typename I> template<typename I2>
"oversampling factor must be a power of 2");
oplus=ilog2(fact);
}
int omax=order_+oplus; // the order up to which we test
size_t omax=size_t(order_)+oplus; // the order up to which we test
// TODO: ignore all disks with radius>=pi
vector<T_Healpix_Base<I> > base(omax+1);
mav<double,3> crlimit({size_t(omax)+1,nv,3});
for (int o=0; o<=omax; ++o) // prepare data at the required orders
for (size_t o=0; o<=omax; ++o) // prepare data at the required orders
{
base[o].Set(o,NEST);
double dr=base[o].max_pixrad(); // safety distance
......@@ -504,18 +504,18 @@ template<typename I> template<typename I2>
}
}
vector<pair<I,int> > stk; // stack for pixel numbers and their orders
vector<pair<I,size_t> > stk; // stack for pixel numbers and their orders
stk.reserve(12+3*omax); // reserve maximum size to avoid reallocation
for (int i=0; i<12; ++i) // insert the 12 base pixels in reverse order
stk.push_back(make_pair(I(11-i),0));
int stacktop=0; // a place to save a stack position
size_t stacktop=0; // a place to save a stack position
while (!stk.empty()) // as long as there are pixels on the stack
{
// pop current pixel number and order from the stack
I pix=stk.back().first;
int o=stk.back().second;
size_t o=stk.back().second;
stk.pop_back();
vec3 pv(base[o].pix2vec(pix));
......@@ -550,14 +550,14 @@ template<typename I> void T_Healpix_Base<I>::query_multidisc_general
}
else // scheme_ == NEST
{
int oplus=inclusive ? 2 : 0;
int omax=min<int>(order_max,order_+oplus); // the order up to which we test
size_t oplus=inclusive ? 2 : 0;
size_t omax=min<size_t>(order_max,size_t(order_)+oplus); // the order up to which we test
// TODO: ignore all disks with radius>=pi
vector<T_Healpix_Base<I> > base(omax+1);
mav<double,3> crlimit({size_t(omax+1),nv,3});
for (int o=0; o<=omax; ++o) // prepare data at the required orders
for (size_t o=0; o<=omax; ++o) // prepare data at the required orders
{
base[o].Set(o,NEST);
double dr=base[o].max_pixrad(); // safety distance
......@@ -569,12 +569,12 @@ template<typename I> void T_Healpix_Base<I>::query_multidisc_general
}
}
vector<pair<I,int> > stk; // stack for pixel numbers and their orders
vector<pair<I,size_t> > stk; // stack for pixel numbers and their orders
stk.reserve(12+3*omax); // reserve maximum size to avoid reallocation
for (int i=0; i<12; ++i) // insert the 12 base pixels in reverse order
stk.push_back(make_pair(I(11-i),0));
int stacktop=0; // a place to save a stack position
size_t stacktop=0; // a place to save a stack position
vector<size_t> zone(nv);
vector<size_t> zstk; zstk.reserve(cmds.size());
......@@ -583,7 +583,7 @@ template<typename I> void T_Healpix_Base<I>::query_multidisc_general
{
// pop current pixel number and order from the stack
I pix=stk.back().first;
int o=stk.back().second;
size_t o=stk.back().second;
stk.pop_back();
vec3 pv(base[o].pix2vec(pix));
......@@ -1161,7 +1161,7 @@ template<typename I> void T_Healpix_Base<I>::neighbors (I pix,
if ((ix>0)&&(ix<nsm1)&&(iy>0)&&(iy<nsm1))
{
if (scheme_==RING)
for (int m=0; m<8; ++m)
for (size_t m=0; m<8; ++m)
result[m] = xyf2ring(ix+nb_xoffset[m],iy+nb_yoffset[m],face_num);
else
{
......@@ -1178,7 +1178,7 @@ template<typename I> void T_Healpix_Base<I>::neighbors (I pix,
}
else
{
for (int i=0; i<8; ++i)
for (size_t i=0; i<8; ++i)
{
int x=ix+nb_xoffset[i], y=iy+nb_yoffset[i];
int nbnum=4;
......
Healpix_cxx/healpix_tables.cc
View file @ 8e9b2689
......@@ -104,9 +104,9 @@ const int Healpix_Tables::nb_swaparray[][3] =
{ 6,0,0 }, // NW
{ 3,0,0 } }; // N
const int Healpix_Tables::swap_clen[] =
const size_t Healpix_Tables::swap_clen[] =
{ 0,7,5,4,12,10,13,18,14,19,18,17,27,21 };
const int Healpix_Tables::swap_cycle[] =
const size_t Healpix_Tables::swap_cycle[] =
{ 0,1,8,12,16,21,40,
0,1,2,40,114,
0,4,160,263,
......
Healpix_cxx/healpix_tables.h
View file @ 8e9b2689
......@@ -60,7 +60,7 @@ class Healpix_Tables
static const int nb_xoffset[], nb_yoffset[],
nb_facearray[][12], nb_swaparray[][3];
static const int swap_clen[], swap_cycle[];
static const size_t swap_clen[], swap_cycle[];
};
}}
......
mr_util/math_utils.h
View file @ 8e9b2689
......@@ -96,7 +96,7 @@ template<typename I> struct isqrt_helper__ <I, true>
static std::uint32_t isqrt (I arg)
{
using namespace std;
I res = std::sqrt(double(arg)+0.5);
I res = I(std::sqrt(double(arg)+0.5));
if (std::uint64_t(arg)<(std::uint64_t(1)<<50)) return std::uint32_t(res);
if (res*res>arg)
--res;
......@@ -114,7 +114,7 @@ template<typename I> inline std::uint32_t isqrt (I arg)
using math_utils_detail::isqrt;
/*! Returns the largest integer \a n that fulfills \a 2^n<=arg. */
template<typename I> inline int ilog2 (I arg)
template<typename I> inline unsigned int ilog2 (I arg)
{
#ifdef __GNUC__
if (arg==0) return 0;
......@@ -125,7 +125,7 @@ template<typename I> inline int ilog2 (I arg)
if (sizeof(I)==sizeof(long long))
return 8*sizeof(long long)-1-__builtin_clzll(arg);
#endif
int res=0;
unsigned int res=0;
while (arg > 0xFFFF) { res+=16; arg>>=16; }
if (arg > 0x00FF) { res|=8; arg>>=8; }
if (arg > 0x000F) { res|=4; arg>>=4; }
......@@ -134,7 +134,7 @@ template<typename I> inline int ilog2 (I arg)
return res;
}
template<typename I> inline int ilog2_nonnull (I arg)
template<typename I> inline unsigned int ilog2_nonnull (I arg)
{
#ifdef __GNUC__
if (sizeof(I)<=sizeof(int))
......
mr_util/rangeset.h
View file @ 8e9b2689
......@@ -88,7 +88,7 @@ template<typename T> class rangeset
size_t slo = sza<szb ? sza : szb,
shi = sza<szb ? szb : sza;
double cost1 = fct1 * (sza+szb);
double cost2 = fct2 * slo * std::max(1,ilog2(shi));
double cost2 = fct2 * slo * std::max(1u,ilog2(shi));
return (cost1<=cost2) ? 1 : (slo==sza) ? 2 : 3;
}
......
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